Question

QUESTION 1 [16 marks] (a) Given that tan x = -\frac{15}{8} and cos y = -\frac{3}{5}, where x lies in the fourth quadrant and 180^\circ \leq y \leq 270^\circ. Find the exact value of sin (x + y). [4]

          QUESTION 1 [16 marks]
(a) Given that
tan x = -\frac{15}{8} and cos y = -\frac{3}{5},
where x lies in the fourth quadrant and 180^\circ \leq y \leq 270^\circ.
Find the exact value of sin (x + y).
[4]

QUESTION 1 [16 marks]
(a) Given that
tan x = -(15)/(8) and cos y = -(3)/(5),
where x lies in the fourth quadrant and 180^∘≤y ≤270^∘.
Find the exact value of sin (x + y).
[4]

Added by Bryan B.

Elementary and Intermediate Algebra

Alan S. Tussy, R. David Gustafson 5th Edition

Instant Answer

Solved by Expert Elizabeth Waters

Step 1

tan(x) = (8√5) / (15√3) Show more…

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[16 marks] Given that 15âˆš3 tan(x) = 8âˆš5 and cos(y) = 8/5 where x lies in the fourth quadrant and 180Â° < y < 270Â° Find the exact value of sin(x + y).