Question

Question 1 22-18. The 50-lb wheel has a radius of gyration about its mass center G of $k_G$ = 0.7 ft. Determine the frequency of vibration if it is displaced slightly from the equilibrium position and released. Assume no slipping. 0.4 ft G 1.2 ft k = 18 lb/ft wwww Strategy

Name: question 1 22 18 the 50 lb wheel has a radius of gyration about its mass center g of kg 07 ft determine the frequency of vibration if it is displaced slightly from the equilibrium position 66556
Uploaded: 2020-10-04T23:27:56-08:00
Duration: 5 min 38 s
Channel: Shoukat Ali
Description: question 1 22 18 the 50 lb wheel has a radius of gyration about its mass center g of kg 07 ft determine the frequency of vibration if it is displaced slightly from the equilibrium position 66556

          Question 1
22-18.
The 50-lb wheel has a radius of gyration about its mass
center G of $k_G$ = 0.7 ft. Determine the frequency of
vibration if it is displaced slightly from the equilibrium
position and released. Assume no slipping.
0.4 ft
G
1.2 ft
k = 18 lb/ft
wwww
Strategy

question 1 22 18 the 50 lb wheel has a radius of gyration about its mass center g of kg 07 ft determine the frequency of vibration if it is displaced slightly from the equilibrium position 66556

Added by Brandon S.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Shoukat Ali

10/04/2020

Step 1

We are given the radius of gyration $k_G = 0.7$ ft and the weight of the wheel $W = 50$ lb. The mass $m$ of the wheel is given by $m = W/g$, where $g = 32.2$ ft/s$^2$. Thus, $m = 50/32.2 = 1.553$ slugs. The mass moment of inertia is given by $I_G = m k_G^2 = 1.553 Show more…

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Question 1 22-18. The 50-lb wheel has a radius of gyration about its mass center G of $k_G$ = 0.7 ft. Determine the frequency of vibration if it is displaced slightly from the equilibrium position and released. Assume no slipping. 0.4 ft G 1.2 ft k = 18 lb/ft wwww Strategy