Question

+5.00 nC of charge is uniformly distributed along the top half of a thin rod of total length L = 1.70 cm, while -5.00 nC of charge is uniformly distributed along the bottom half of the rod, as shown in the figure. What is the magnitude of the electric field at the dot, a distance r = 12.8 cm from the centre of the rod? Magnitude: 

          +5.00 nC of charge is uniformly distributed along the top half of a thin rod of total length L = 1.70 cm, while -5.00 nC of charge is uniformly distributed along the bottom half of the rod, as shown in the figure. What is the magnitude of the electric field at the dot, a distance r = 12.8 cm from the centre of the rod?
Magnitude:
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+5.00 nC of charge is uniformly distributed along the top half of a thin rod of total length L = 1.70 cm, while -5.00 nC of charge is uniformly distributed along the bottom half of the rod, as shown in the figure. What is the magnitude of the electric field at the dot, a distance r = 12.8 cm from the centre of the rod? Magnitude:

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University Physics with Modern Physics
University Physics with Modern Physics
Hugh D. Young 14th Edition
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+5.00 nC of charge is uniformly distributed along the top half of a thin rod of total length L = 1.70 cm, while -5.00 nC of charge is uniformly distributed along the bottom half of the rod, as shown in the figure. What is the magnitude of the electric field at the dot, a distance r = 12.8 cm from the center of the rod? Magnitude:
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Transcript

-
00:01 Hello everyone.
00:03 So in this question we have to find the magnitude of net electric field.
00:13 Right? so, considering the figure 1, we have ex in general terms is given as lambda divided by 4 pi epsilon knot in rapid 1 divided by square root, d square plus r square plus 1 divided by r whereas ey is given as lambda divided by four by epsilon not r in bracket d divided by square root d square plus r square now let a represent coming to figure b let a represent a positively charged part whereas b represent the negatively charged part then we have x that is equals to x a plus e x b which is equal to x a plus x b which is equal to 1 divided by 4 pi epsilon knot in bracket we have 1 divided by square root half of l that is l divided by 2 square plus r square plus 1 divided by i or multiplied by lambda a plus lambda b further lambda a and lambda b can be written as 1 divided by 4 pi epsilon not in bracket 1 divided by square root l divided by 2 square plus r square plus 1 divided by r q a divided by half of l plus qb half of l.
02:54 If the values are epsilon 0 is equal to 8 .854, multiplied by 10 raise to the pi minus 12.
03:13 Value of l is 0 .117.
03:18 Value of r is 0 .128 meter, meter.
03:32 Further value of qa is 5 nanoclome.
03:43 And qb is minus 599.
03:50 Substituting all these values in solving, we get x equals to 0...
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