Question 1 8 pts A first order reaction rate constant has a frequency factor of 2,437,596,748,678 s^(-1) and an activation energy of 58 kJ/mol. Determine the rate constant $k$ to 2 decimal places. The temperature is 400 K. Use the value of R equal to 0.008314 kJ/mol*K.
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Activation energy = 58 kJ/mol * 1000 J/kJ = 58000 J/mol Show more…
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