Question 1 A 200 HF capacitor is charged to 26 V and then discharged through a \( 40 \mathrm{~K} \Omega \) ressistor. (a) Caculate the intital current in the resistior. (b) (i) Ater 5.5 s the p.d. has fallen to 13 V . Find the p.d. atere another 5.5 s. (ii) Calculate the curenti in the ressistor at 11 s . (c) Calculate (i) the p.d. and (fii) the curerent in the ressistor aferer 8.0 s. (d) Show thet the values in ic) are related to the values in (b) by a factor close to 0.69 which in in? (e) How ing does it the for the p.d. to ta to to 1.0 V ?
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- Use Ohm's Law: \( I = \frac{V}{R} \). - Initial voltage \( V = 26 \, \text{V} \). - Resistance \( R = 40 \, \text{k}\Omega = 40,000 \, \Omega \). \[ I = \frac{26}{40,000} = 0.00065 \, \text{A} = 0.65 \, \text{mA} \] Show more…
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