00:01
It is known that there are three restaurants denoted as i, j and w.
00:07
Out of these three restaurants, burgers are bought and the level of grease in them as is being tested.
00:17
Now we have to check whether the level of grease is same or significantly different between these all restaurant burgers.
00:28
So the null hypothesis will be h0 equals to mu i equals to mu j equals to mu w, where mu stands for the mean level of grease in burgers from the three restaurants.
00:43
The alternative hypothesis being that at least one of the burgers differ in the level of greaseness.
00:55
So for doing this since there are now more than two groups we have to apply anova test.
01:05
So we are asked if this anova test conducted here is depending upon the between groups test or within group test.
01:17
Now we know that the burgers here are tested between the restaurants.
01:24
The three different restaurants, that means the burgers are tested for three different groups.
01:33
They are not tested for the similarity within their own restaurant.
01:39
They are tested whether they differ between these groups.
01:43
Therefore, the answer is that the anova test conducted here is between group test.
01:51
Now we have to find the f critical.
01:54
Value for the given case.
01:57
For this we have to conduct the anova test for the data given.
02:03
This can be done using minutap...