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Question 1 An electron experiences a force of magnitude 12.0 N when it is 2.00 cm from a very long charged wire with linear charge density ?. What force does the electron experience if the distance is doubled? 24.0 N/C 6.00 N/C 12.0 N/C 3.00 N/C Question 2 Two charged, square plates, separated by a distance of 22.4 cm and each with a side length of 41.0 cm, make up a parallel-plate capacitor. The electric field inside the plates is 2.10×10³ N/C. If the side length is doubled (but leaving the total charge the same), what would the electric field inside the plates become? 1.05E+03 N/C 525 N/C 2.10E+03 N/C 4.20E+03 N/C Question 3 In the figure above, a positive object at position 2 is let go from rest. Describe the object's motion. It moves to the left at constant speed. It moves to the right at constant speed. It accelerates to the right. It remains at the same position. It accelerates to the left. Question 4 An electric dipole is shown above with charges ±q and seprated by distance r. What is the correct direction of the electrc field at point P? b a c

          Question 1
An electron experiences a force of magnitude 12.0 N when it is 2.00 cm from a very long charged wire with linear charge density ?. What force does the electron experience if the distance is doubled?
24.0 N/C
6.00 N/C
12.0 N/C
3.00 N/C
Question 2
Two charged, square plates, separated by a distance of 22.4 cm and each with a side length of 41.0 cm, make up a parallel-plate capacitor. The electric field inside the plates is 2.10×10³ N/C. If the side length is doubled (but leaving the total charge the same), what would the electric field inside the plates become?
1.05E+03 N/C
525 N/C
2.10E+03 N/C
4.20E+03 N/C
Question 3
In the figure above, a positive object at position 2 is let go from rest. Describe the object's motion.
It moves to the left at constant speed.
It moves to the right at constant speed.
It accelerates to the right.
It remains at the same position.
It accelerates to the left.
Question 4
An electric dipole is shown above with charges ±q and seprated by distance r. What is the correct direction of the electrc field at point P?
b
a
c

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Question 1
An electron experiences a force of magnitude 12.0 N when it is 2.00 cm from a very long charged wire with linear charge density ?. What force does the electron experience if the distance is doubled?
24.0 N/C
6.00 N/C
12.0 N/C
3.00 N/C
Question 2
Two charged, square plates, separated by a distance of 22.4 cm and each with a side length of 41.0 cm, make up a parallel-plate capacitor. The electric field inside the plates is 2.10×10³ N/C. If the side length is doubled (but leaving the total charge the same), what would the electric field inside the plates become?
1.05E+03 N/C
525 N/C
2.10E+03 N/C
4.20E+03 N/C
Question 3
In the figure above, a positive object at position 2 is let go from rest. Describe the object's motion.
It moves to the left at constant speed.
It moves to the right at constant speed.
It accelerates to the right.
It remains at the same position.
It accelerates to the left.
Question 4
An electric dipole is shown above with charges ±q and seprated by distance r. What is the correct direction of the electrc field at point P?
b
a
c

Added by Roni J.

University Physics with Modern Physics

Hugh D. Young 14th Edition

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Solved by Expert Vishal Gupta

01/30/2023

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0 N when it is 2.00 cm from the long charged wire. Show more…

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Question 1: An electron experiences a force of magnitude 12.0 N when it is 2.00 cm from a very long charged wire with linear charge density λ. What force does the electron experience if the distance is doubled? Question 2: Two charged, square plates, separated by a distance of 22.4 cm and each with a side length of 41.0 cm, make up a parallel-plate capacitor. The electric field inside the plates is 2.10×10^3 N/C. If the side length is doubled (but leaving the total charge the same), what would the electric field inside the plates become? Question 3: In the figure above, a positive object at position 2 is let go from rest. Describe the object's motion. Question 4: An electric dipole is shown above with charges ±q and separated by distance r. What is the correct direction of the electric field at point P?

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Transcript

00:02 Hi, here there are four short questions in this given problem.

00:06 First of all, this is the question number one.

00:11 And in it this is a force.

00:15 Force experienced by the electron that is given to be 12 .0 newton when this electron is at a distance of r1 is equal to 2 .00 cm from the linear charged conductor.

00:43 Now further the distance is increased to twice of the original one means, 2r1 means this is 4 .00 centimeter now.

00:55 And here we have to find the force experienced by the same electron.

01:00 So using an expression for the electric field around a charged conductor, a linear charge conductor, and that is one of a one.

01:12 By 4 pi epsilon knot, multiplied by 2 lambda by r, where lambda is the linear charge density, and one more expression that is for force which is given as the product of charge carried by electron with the electric field.

01:30 So here it is 1 by 4 pi epsilon not, multiplied by 2 lambda e by r.

01:37 Overall, we conclude that the force depends inversely on the distance of the charged particle from the linear conductor.

01:47 So, on making the distance double as r2 is twice of r1, simply implies the force should be reduced to half as they depend inversely on each other.

02:05 Means initially the force was 12 newton.

02:08 So finally it should be 12 by 2 means it should be 6 .00 newton.

02:14 So we conclude here the second option is correct.

02:22 Then in the next one this is the question number 2.

02:29 The gap between the parallel plates of a capacitor.

02:39 This is given as 22 .4 centimeter and side length of the square plate that is a is equal to 41 .0 centimeter in this case electric field between the plates that is having a magnitude 2 .10 multiplied by 10 dashed by 3 newton per coula.

03:08 Now the side length is made twice.

03:13 So simply area of the plates it will become four times of the initial one...

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