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Question 1: Coupled reactions: Free energy coupling (Total of 15 points) Part A: (8 points) For the reaction: Fructose-6-Phosphate (aq) + ATP (aq) → Fructose-1,6-bis-Phosphate (aq) + ADP (aq) at 37ºC, the standard Gibbs energy (at pH=7) is -18.3 kJ/mol. The concentration of fructose 6-phosphate (F6P) and fructose 1,6-bisphosphate (F16bP), ATP, and ADP in muscle tissue were measured as 0.089, 0.012, 12.0, and 1.2 mmol/L. Calculate: i) The reaction quotient ii) The Gibbs energy for the reaction in muscle at 37oC, which is not at standard-state (3 points) iii) Is the reaction spontaneous? (2 points) Part B: i) Calculate the equilibrium constant of the phosphorylation of glucose at 37oC, as indicated by the equation below. The Gibbs energy for the reaction is -34 kJ/mol at 310K. Glucose (aq) + ATP (aq) = G-6-P (aq) + ADP (aq) + H+ (aq) ii) What does the value of the equilibrium constant say about the direction of the reaction?

          Question 1: Coupled reactions: Free energy coupling
(Total of 15 points)

Part A: (8 points)

For the reaction:
Fructose-6-Phosphate (aq) + ATP (aq) → Fructose-1,6-bis-Phosphate (aq) + ADP (aq)
at 37ºC, the standard Gibbs energy (at pH=7) is -18.3 kJ/mol.

The concentration of fructose 6-phosphate (F6P) and fructose 1,6-bisphosphate (F16bP), ATP, and ADP in muscle tissue were measured as 0.089, 0.012, 12.0, and 1.2 mmol/L.

Calculate:
i) The reaction quotient
ii) The Gibbs energy for the reaction in muscle at 37oC, which is not at standard-state (3 points)
iii) Is the reaction spontaneous? (2 points)

Part B:
i) Calculate the equilibrium constant of the phosphorylation of glucose at 37oC, as indicated by the equation below. The Gibbs energy for the reaction is -34 kJ/mol at 310K.
Glucose (aq) + ATP (aq) = G-6-P (aq) + ADP (aq) + H+ (aq)
ii) What does the value of the equilibrium constant say about the direction of the reaction?

Added by Michael H.

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