Let $W = log_b(3)$. Condense the logarithm and write your answer as a multiple of $W$. $frac{1}{3}log_b(64) - log_b(12)$ Do not solve for $b$.
Added by Martin R.
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Then, we can rewrite the given expression as 3A * 6logb(2) * (2logb(3) + logb(2)). This simplifies to 18Alogb(2) * 2logb(3) + 18Alogb(2)^2. We know that logb(2) = W/logb(3), so we can substitute this into the expression. Show more…
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