0.2 kg/s of saturated vapor R134a enters an adiabatic and reversible compressor with at -12°C and exits with a pressure of 800 kPa. Compute the power input to the compressor. Select one: a. 5 kW b. 3 kW c. 4 kW d. 6 kW
Added by Juan Manuel P.
Close
Step 1
Given that the saturated vapor enters the compressor at -12°C, we can use the saturation table for R134a to find the corresponding pressure at this temperature. From the table, we find that the saturation pressure at -12°C is approximately 0.45 MPa. Show more…
Show all steps
Your feedback will help us improve your experience
Ethan Deweese and 61 other Physics 101 Mechanics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Saturated R-134a vapour at 340 kPa is compressed to superheated vapour with enthalpy equal to 345 kJ/kg. The compressor has an efficiency of 0.91 and requires 26 kW of power. Calculate the mass flow rate of the refrigerant to 2 decimal places. Give your answer in kg/s.
Adi S.
An ideal vapor-compression refrigeration cycle operates at a steady state with Refrigerant 134a as the working fluid. Saturated vapor enters the compressor at -10°C, and saturated liquid leaves the condenser at 28°C. The mass flow rate of refrigerant is 5 kg/min. Show the process on a T-S diagram, labeling the two temperatures on the y-axis, and determine: (a) The compressor power, in kW. (b) The refrigerating capacity (Q̇in), in tons (1 ton = 211 kJ/min). (c) The coefficient of performance. Take: h_evaporator,out = h_compressor,in = 241.35 kJ/kg h_compressor,out = h_condenser,in = 267.9 kJ/kg h_valve,out = h_evaporator,in = 88.61 kJ/kg
Saturated R-134a vapour at 340 kPa is compressed to superheated vapour with enthalpy equal to 314.8 kJ/kg. The compressor has an efficiency of 0.92 and requires 21 kW of power. Calculate the mass flow rate of the refrigerant in kg/s to 2 decimal places.
Madhur L.
Recommended Textbooks
University Physics with Modern Physics
Physics: Principles with Applications
Fundamentals of Physics
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD