Question

Question 1 of 15 How many moles of lithium hydroxide would be required to produce 67.5 g of $Li_2CO_3$ in the following chemical reaction? $2 LiOH(s) + CO_2(g) \rightarrow Li_2CO_3(s) + H_2O(l)$

          Question 1 of 15
How many moles of lithium hydroxide would be required to produce
67.5 g of $Li_2CO_3$ in the following chemical reaction?
$2 LiOH(s) + CO_2(g) \rightarrow Li_2CO_3(s) + H_2O(l)$

Question 1 of 15
How many moles of lithium hydroxide would be required to produce
67.5 g of Li2CO3 in the following chemical reaction?
2 LiOH(s) + CO2(g) → Li2CO3(s) + H2O(l)

Added by Pilar R.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

Instant Answer

Solved by Expert Amita Prajapat

01/30/2022

Step 1

The molar mass of Li₂CO₃ can be calculated by adding the molar masses of lithium (Li), carbon (C), and oxygen (O). Molar mass of Li₂CO₃ = 2(Li) + 1(C) + 3(O) = 2(6.94 g/mol) + 12.01 g/mol + 3(16.00 g/mol) = 73.89 g/mol Show more…

Show all steps

Thanks for your feedback!

Question 1 of 15 How many moles of lithium hydroxide would be required to produce 67.5 g of Li₂CO₃ in the following chemical reaction? 2 LiOH(s) + CO₂(g) → Li₂CO₃(s) + H₂O(l)