Question

Level 1 ( (4) 1) (4) Match each graph with its correct equation. A. $(x-1)^2 + (y-1)^2 = 9$ B. $(x-1)^2 + (y+1)^2 = 9$ C. $(x+1)^2 + (y-1)^2 = 9$ D. $(x+1)^2 + (y+1)^2 = 9$ a) b) c) d) Level 2 ( /14) 2) (4) Given the equation for a circle find the information asked for below. Show all work! $25 = (x - 1)^2 + (y + 2)^2$ a) What is the center of the circle? (1, -2) b) What is the length of the radius? 5 c) Graph the circle to the right on the graph. 3) (2) Find the area of the shaded region of the circle given. Show all work! 7 m 165° $\frac{360}{165}$ $\frac{195}{360} \pi r^2 \approx 83.4$ Sector Area= 83.4 4) (4) What portion or percent of the circle is shaded if the area of the shaded sector is 424.16 cm²? a) 15 cm $C = 2\pi r = 15\pi = 94.25$ $\frac{424.16}{23715} = \frac{x}{360}$ $360 \times 4.5 = 360$ $360 \times 4.5 = x$ $1620$ Portion/percent: 5) (4) If the shaded sector represents 1/3 of the circle and the sector area is 150.8 in², what would the radius be? b) $\frac{150}{3} = 50$ r Radius:

          Level 1 (
(4)
1) (4) Match each graph with its correct equation.
A. $(x-1)^2 + (y-1)^2 = 9$
B. $(x-1)^2 + (y+1)^2 = 9$
C. $(x+1)^2 + (y-1)^2 = 9$
D. $(x+1)^2 + (y+1)^2 = 9$
a) b) c) d)
Level 2 (
/14)
2) (4) Given the equation for a circle find the information asked for below. Show all work!
$25 = (x - 1)^2 + (y + 2)^2$
a) What is the center of the circle? (1, -2)
b) What is the length of the radius? 5
c) Graph the circle to the right on the graph.
3) (2) Find the area of the shaded region of the circle given. Show all work!
7 m
165°
$\frac{360}{165}$
$\frac{195}{360} \pi r^2 \approx 83.4$
Sector Area= 83.4
4) (4) What portion or percent of the circle
is shaded if the area of the shaded sector is
424.16 cm²?
a)
15 cm
$C = 2\pi r = 15\pi = 94.25$
$\frac{424.16}{23715} = \frac{x}{360}$
$360 \times 4.5 = 360$
$360 \times 4.5 = x$
$1620$
Portion/percent:
5) (4) If the shaded sector represents 1/3 of
the circle and the sector area is 150.8 in², what
would the radius be?
b)
$\frac{150}{3} = 50$
r
Radius:
        
Show more…
Level 1 (
(4)
1) (4) Match each graph with its correct equation.
A. (x-1)^2 + (y-1)^2 = 9
B. (x-1)^2 + (y+1)^2 = 9
C. (x+1)^2 + (y-1)^2 = 9
D. (x+1)^2 + (y+1)^2 = 9
a) b) c) d)
Level 2 (
/14)
2) (4) Given the equation for a circle find the information asked for below. Show all work!
25 = (x - 1)^2 + (y + 2)^2
a) What is the center of the circle? (1, -2)
b) What is the length of the radius? 5
c) Graph the circle to the right on the graph.
3) (2) Find the area of the shaded region of the circle given. Show all work!
7 m
165°
(360)/(165)
(195)/(360)π r^2 ≈ 83.4
Sector Area= 83.4
4) (4) What portion or percent of the circle
is shaded if the area of the shaded sector is
424.16 cm²?
a)
15 cm
C = 2π r = 15π = 94.25
(424.16)/(23715) = (x)/(360)
360 × 4.5 = 360
360 × 4.5 = x
1620
Portion/percent:
5) (4) If the shaded sector represents 1/3 of
the circle and the sector area is 150.8 in², what
would the radius be?
b)
(150)/(3) = 50
r
Radius:

Added by Encarnacion G.

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Geometry A Common Core Curriculum
Geometry A Common Core Curriculum
Ron Larson, Laurie Boswell 1st Edition
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Question 1 ONLY, thank you. Levela /4) 1( /4Match each graph withits correct.equation Ax1y=9 cxy=9 Bx+y+1=9 Dx+1+y1=9 Level2 2 /4) Given the equation for a circle find the information asked for belowShow all work! 25=x-1+y+2 aWhat is the center of the circle? b) What is the length of the radius?5 c Graph the circle to the right on the graph 3 /2Find the area of the shaded region of the circle given.Show all work! E 2 165 300 165 195 195 Sector Area=3.y 4/4What portion or percent of the circle 5/4If the shaded sector represents 1/3of is shaded if the area of the shaded sector is the circle and the sector area is 150.8 in,what 424.16cm7 would the radius be? a) C=2T15=94.25 b 150 424.16 X =50 33215 3 2TT15 306 206 X 15cm 3604.5 =h008 1620 Portion/percent: Radius:
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Transcript

-
00:01 All right, to kind of set this up, what i've done is created some formulas to kind of look at through things.
00:08 So first things first, we have a quarter circle up here in the upper left hand corner.
00:13 We're going to use that to find the lens shape or those overlapping semi -circles.
00:19 So i need to subtract the triangle in red from the semicircle.
00:25 And that's going to leave me the top half of that lens shape.
00:28 I can double it because those pieces are symmetrical to get the actual area of that space occupied by those two semicircles.
00:38 So what i do is i obviously plug in my values.
00:42 I have one quarter times pi times r.
00:51 Keep in mind if the square has a side length of 10, the radius of that circle is 5.
00:59 We find out that a quarter circle or the area occupied by a quarter circle is about 19 .6.
01:07 I'm going to use that stored value in my calculator to get a more exact answer in the end.
01:14 When looking at the triangle, we know the base and the height of the triangle are both five.
01:20 Half of 25 is 12 .5.
01:25 So what i can do again is subtract the two or find the difference of the two...
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