00:02
So for this problem, we're asked to find the temperature of the initial plate initially.
00:07
In order to do so, we need to first of all calculate the heat loss to convection as well as the heat loss to conduction.
00:18
So what we need to do is because the conservation of energy statement tells us that the heat loss of heat created by conduction has to be equal to the heat loss of convection and heat loss of radiation.
00:29
So we're given heat loss of radiation.
00:32
We also have the ha and the ts and t infinity values in order to find the heat loss of convection.
00:39
And then we can use these two combined to find the heat loss of conduction.
00:44
And the heat loss of conduction equation is negative k times a times the change in temperature over change in x, x being the width or the depth of the plate.
01:00
And then if you rewrite that, you get that the change in temperature is this equation right here.
01:05
So the change in depth times the heat loss of conduction, or heat created by conduction, divide by the k times a.
01:15
So let's go ahead and take this step by step.
01:17
So the first step would be to solve for the heat loss of convection, which would be 22 times 0 .54 times 310 minus 15.
01:34
So that results in 3 ,504 .6 watts...