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QUESTION 1 (Superposition Theorem) Use Superposition theorem to obtain the current flowing in the (4+ j3) ?. A $-j10 \Omega$ $V_1 =$ $30\angle 45^\circ V$ 4 ? $j3 \Omega$ $V_2 =$ $30\angle -45^\circ V$ 4 ? B [26]

          QUESTION 1 (Superposition Theorem)
Use Superposition theorem to obtain the current flowing in the (4+ j3) ?.
A
$-j10 \Omega$
$V_1 =$
$30\angle 45^\circ V$
4 ?
$j3 \Omega$
$V_2 =$
$30\angle -45^\circ V$
4 ?
B
[26]

QUESTION 1 (Superposition Theorem)
Use Superposition theorem to obtain the current flowing in the (4+ j3) ?.
A
-j10 Ω
V1 =
30∠ 45^∘ V
4 ?
j3 Ω
V2 =
30∠ -45^∘ V
4 ?
B
[26]

Added by James G.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Ameer Said

01/13/2022

Step 1

The impedance seen by $V_1$ is $Z_1 = 4 + \frac{(-j10)(4)}{-j10 + 4} = 4 + \frac{-j40}{4 - j10} = 4 + \frac{-j40(4 + j10)}{16 + 100} = 4 + \frac{400 - j160}{116} = 4 + 3.45 - j1.38 = 7.45 - j1.38 \Omega$. The current $I_{1}$ flowing through the (4+j3)Ω impedance Show more…

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QUESTION 1 (Superposition Theorem) Use Superposition theorem to obtain the current flowing in the (4+ j3) Ω. $V_1 = 30\angle 45^\circ V$ $V_2 = 30\angle -45^\circ V$