Question 1: This is a consecutive reaction with irreversible first-order reactions. Suppose that A → k1 B → k2 C. And you are interested in isolating the largest possible amount of B. Given the values of k1 and k2, derive an equation for the time that the concentration of B goes through the maximum. Now consider two cases: (a) A reacts more rapidly than B and (b) A reacts less rapidly than B. For a given value of k2, in which case would you wait the longer time for B to go through its maximum?
Hint: Start by writing out the differential equations for each step (i.e. d[A]/dt = -k1[A]). Then solve for d[B]/dt. 2nd hint: [B] is maximum when d[B]/dt = 0.
Question 2: Nth order derivation for half-life (t %):
The reaction A → B is nth order (where n = %, 3/2, 2, 3, etc.) and goes to completion to the right. Derive the expression for the half-life as a function of k and [A].
Question 3: Steady-state approximation problem:
Consider the following reaction mechanism:
A + B → C → D
Hint: The reverse reaction for C → A + B should be k-1.
Derive the rate law using the steady-state approximation to eliminate the concentration [C]. (b) Assuming that k-1 << k1, express the pre-exponential factor A and activation energy Ea for the apparent second-order rate constant in terms of A1, A2, and A3, and Ea1, Ea2, and Ea3 for the three steps.