$x^2 + y^2 - 2x + 4y + 1 = 0$ is the equation of a circle with center $(h, k)$ and radius $r$ for: h = and k = and r = Graph the circle.
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To find the values of h, k, and r, we need to rewrite the equation in standard form, which is in the form (x - h)^2 + (y - k)^2 = r^2. Given equation: -2x + 4y + 1 = 0 To rewrite it in standard form, we need to complete the square for both x and y terms. Show more…
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