Vcc = +10.0 V Rc 330 ? RB ?DC = 100 Refer to Figure 5. When conducting, assume the LED drops 1.8 V and VCE(sat) = 0.2 V. Then the current in the LED will be approximately
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Since Vc is +10.0V and the LED drops 1.8V, the voltage across Rc will be 10.0V - 1.8V = 8.2V. Show more…
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