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Question 13 ( 10 points) Consider a convergent divergent nozzle in which steam enters at 0.8 MP and leaves the nozzle at 0.15 MPa , Assuming isentropic expansion and index $ \mathrm{n}= $ 1.135, find the ratio of cross-sectional area at the exit to the area at the throat for choked conditions $ A_{1} / A_{2} $. Critical pressure for maximem matr flow is given: Form the Mollict chant \[ \boldsymbol{P}_{\mathbf{c}}=\boldsymbol{P}_{\mathbf{2}}=P_{1}\left(\frac{2}{n+1}\right)^{\frac{n}{n-1}}=0.8\left(\frac{2}{2.135}\right)^{2+1}=0.462 \mathrm{MPa} \] $ \mathrm{h}_{1}=2769 \mathrm{k} / \mathrm{k}, \quad h_{2}=2659 \mathrm{~kJ} / \mathrm{kg} . \quad h_{y}=2452 \mathrm{~kJ} / \mathrm{kg} $ Dryness fraction: $ x=0.954, v_{g 2}=0.4038 \mathrm{m3} \mathrm{dg} $ Drness fraction: $ \left.x_{j}=0.902, v_{g}\right)=1.1593 \mathrm{m3} / \mathrm{kg} $

          Question 13 ( 10 points)

Consider a convergent divergent nozzle in which steam enters at 0.8 MP and leaves the nozzle at 0.15 MPa , Assuming isentropic expansion and index \( \mathrm{n}= \) 1.135, find the ratio of cross-sectional area at the exit to the area at the throat for choked conditions \( A_{1} / A_{2} \).

Critical pressure for maximem matr flow is given:

Form the Mollict chant
\[
\boldsymbol{P}_{\mathbf{c}}=\boldsymbol{P}_{\mathbf{2}}=P_{1}\left(\frac{2}{n+1}\right)^{\frac{n}{n-1}}=0.8\left(\frac{2}{2.135}\right)^{2+1}=0.462 \mathrm{MPa}
\]
\( \mathrm{h}_{1}=2769 \mathrm{k} / \mathrm{k}, \quad h_{2}=2659 \mathrm{~kJ} / \mathrm{kg} . \quad h_{y}=2452 \mathrm{~kJ} / \mathrm{kg} \)
Dryness fraction: \( x=0.954, v_{g 2}=0.4038 \mathrm{m3} \mathrm{dg} \)
Drness fraction: \( \left.x_{j}=0.902, v_{g}\right)=1.1593 \mathrm{m3} / \mathrm{kg} \)

$Question 13 ( 10 points) Consider a convergent divergent nozzle in which steam enters at 0.8 MP and leaves the nozzle at 0.15 MPa , Assuming isentropic expansion and index n= 1.135, find the ratio of cross-sectional area at the exit to the area at the throat for choked conditions A1 / A2. Critical pressure for maximem matr flow is given: Form the Mollict chant P𝐜=P2=P1((2)/(n+1))^(n)/(n-1)=0.8((2)/(2.135))^2+1=0.462 MPa h1=2769 k / k, h2=2659 kJ / kg . hy=2452 kJ / kg Dryness fraction: x=0.954, vg 2=0.4038 m3dg Drness fraction: .xj=0.902, vg)=1.1593 m3 / kg$

Added by Margaret P.

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