Question

Question 13 A series RLC circuit has a resistor of 500 ?, an inductor of 25 mH, and a capacitor of 1.4 ?F. The AC voltage source has peak voltage V0 = 10 V. At a radial frequency of ? = 2700 rad/s, what is the capacitive reactance of the capacitor and the inductive reactance of the inductor? O Xc = 265 ?, Xl = 67.5 ? O Xc = 3.77 m?, Xl = 67.5 ? O Xc = 265 ?, Xl = 14.8 m? O Xc = 3.77 m?, Xl = 14.8 m?

          Question 13

A series RLC circuit has a resistor of 500 ?, an inductor of 25 mH, and a capacitor of 1.4 ?F. The AC voltage source has peak voltage V0 = 10 V. At a radial frequency of ? = 2700 rad/s, what is the capacitive reactance of the capacitor and the inductive reactance of the inductor?

O Xc = 265 ?, Xl = 67.5 ?
O Xc = 3.77 m?, Xl = 67.5 ?
O Xc = 265 ?, Xl = 14.8 m?
O Xc = 3.77 m?, Xl = 14.8 m?

Question 13

A series RLC circuit has a resistor of 500 ?, an inductor of 25 mH, and a capacitor of 1.4 ?F. The AC voltage source has peak voltage V0 = 10 V. At a radial frequency of ? = 2700 rad/s, what is the capacitive reactance of the capacitor and the inductive reactance of the inductor?

O Xc = 265 ?, Xl = 67.5 ?
O Xc = 3.77 m?, Xl = 67.5 ?
O Xc = 265 ?, Xl = 14.8 m?
O Xc = 3.77 m?, Xl = 14.8 m?

Added by Concepci-N F.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Madhur L

07/24/2023

Step 1

Given that the radial frequency ω = 2700 rad/s, we can calculate the frequency f as f = ω / (2 * π) = 2700 / (2 * π) ≈ 429.29 Hz. Plugging in the values, we get Xc = 1 / (2 * π * 429.29 * 1.4e-6) ≈ 2650 Ω. Show more…

Show all steps

Thanks for your feedback!

A series RLC circuit has a resistor of 500 Ω, an inductor of 25 mH, and a capacitor of 1.4 μF. The AC voltage source has peak voltage V0 = 10 V. At a radial frequency of ω = 2700 rad/s, what is the capacitive reactance of the capacitor and the inductive reactance of the inductor? Options: Xc = 265 Ω, Xl = 67.5 Ω Xc = 3.77 mΩ, Xl = 67.5 Ω Xc = 265 Ω, Xl = 14.8 mΩ Xc = 3.77 mΩ, Xl = 14.8 mΩ