QUESTION 14 A solid circular shaft is subjected to a bending moment of 3 kN.m and a torque of 10 kN.m. The shaft is made of steel having ultimate tensile stress of 700 MPa and ultimate shear stress of 500 MPa. Assuming a factor of safety as 6, Determine the following: • Equivalent twisting moment (kN.m) : • Equivalent bending moment (kN.m) : • The diameter of the shaft (using maximum normal stress theory) (mm) : • The diameter of the shaft (using maximum shear stress theory) (mm) : QUESTION 15 The standard cross-section for a flat key, which is fitted on an 41 mm diameter shaft, is 16 mm wide and 12 mm height. The key is transmitting 545 N.m torque from the shaft to the hub. The key is made of commercial steel (Syt = 400 N/mm² ; Syc = 219 N/mm²). The factor of safety is 3. Determine the minimum required length of the key for compression (mm)?
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Calculate the equivalent twisting moment: Mtw = (545 N.m) (16 mm) (12 mm) = 9,000 N.m Show more…
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Question 3: The 60 mm diameter solid shaft is subjected to the distributed and concentrated torsional loadings shown. Determine the absolute maximum and minimun shear stresses on the outer surface of the shaft and specify their locations, measured from the fixed end A. Take : AA = 1.57 m BB = 0.87 m CC = 1207 kN/m Solution : The internal torque for segment BC is Constant T_BC = CC Nm. However, the internal for segment AB varies with x, T_AB - 2000x + AA = 0; T_AB = (2000x - CC) Nm The minimum shear stress occurs when the internal torque is zero in segment AB. By setting T_AB = 0 0 = (2000x - CC); x = [] m Ans And d = AA - x = [] m Ans T_min = [] Ans The maximum shear stress occurs when the internal torque is the greatest. This occurs at fixed support A where d = [] m Ans At this location, (T_AB)_max = 2000AA - CC = [] The polar moment of inertia of the rod is J = pi/2 (0.03^4) = 0.405(10^-6)pi. Thus, T_max = (T_AB)_max c / J = (0.03)(T_AB)_max / 0.405(10^-6)pi = [] MPa Ans
Sri K.
1. A 45 mm diameter shaft is made of steel with a yield strength of 400 MPa. A parallel key of size 14 mm width and 9 mm thickness made of steel with a yield strength of 340 MPa is to be used. Find the required length of key, if the shaft is loaded to transmit the maximum permissible torque. Use maximum shear stress theory and assume a factor of safety of 2.
Supreeta N.
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