00:02
So now we'll work on problem 90 from chapter 21.
00:08
Here we're asked to identify all the functional groups in the molecules, or the functional group that's present in each structure, and then provide the name of each compound.
00:25
So let's go ahead and write the structure we're given for part a.
00:29
And that's ch3, ch3, chc, c, double wand, c, c, c, h, h, c, h, c, h, c, and let's add in three methyl groups.
00:55
So first, let's identify the functional group that we have here, and that's an alken because of the double bond.
01:04
And then we want to name our carbons, a number our carbons, and we'll start on the side that's closer to the double bond.
01:11
So 1, 2, 3, 4, and 5.
01:20
So now we can list our substituents and their position.
01:24
So 2, 3, 4, trymethyl.
01:35
And we have 5 carbons and a double bond at position 2, so it's 2pentine.
01:46
So let's move to part b, where we're given the following structure.
02:07
And drawing our substituents.
02:19
This is an alkan due to the fact that we have a saturated hydrocarbon.
02:30
So let's go ahead and name a number our carbons.
02:33
And since we have no double bonds or functional groups, we will start from the side that has more substituents.
02:42
One, two, three, four, five, and six.
02:49
So we number our substituents and get 2 -4 trimethyl.
03:02
And then we have a 6 -carbon chain, so just hexane.
03:09
So we can move on to part c.
03:17
Here we are given the following structure.
03:42
And we know we have a substituent here, and we know that this double bond o -oh is indicative of a carbux acid, and you have a five carbon chain, which will give rise to the p and t prefix.
04:08
We'll number our carbons starting from the carbonylacilic acid, 3, 4, and 5, and we can write our name numbering the substituents first, so 3 -methyl, pentanote, no position there, pentanoic acid.
04:29
The carboxylic acid has to be on the end...