00:01
So, here according to the question, if we first of all write the given part, ok, so there is a line like this and a point here, ok, so from this point at an angle alpha we have a force which is 100 newton, ok.
00:16
Then here it is also a force which is 150 newton in magnitude and this angle it is given 30 degree, ok.
00:25
And here there is another force, let us say this angle is alpha, given in the question it is 200 newton in magnitude and this is our vertical, ok.
00:39
So according to the question it is also given that alpha value is 35 degree, ok.
00:45
So if we take components, so first of all let us take the components in vertical direction, ok.
00:50
So in the vertical direction, the component of 100 newton, ok, if this angle is alpha, we know that whenever there is a force like this f, so its vertical component if this angle is theta, it is f sin theta, ok.
01:07
So similarly here we are going in negative y axis, so in magnitude we will write it positive but when we add them we will put the minus sign, ok.
01:15
So it is 100 newton and this angle is alpha, so it will be 100 sin alpha and alpha value is 35 degree.
01:22
So 100 sin 35 degree, ok, plus because these will be, these all forces, vertical components will be add up because they are in negative y axis, ok, plus the component of 150 newton in negative y axis, so it will be 150 and sin 30 degree, sorry sin 30 degree plus 35 degree because from x axis this whole angle will be 30 degree plus 35 degree, ok, which will be equal to 65, so 150 sin 65 degree plus the component of 200 newton, so 200 sin 35 degree, ok.
01:59
So this is our vertical components, ok.
02:03
So let us not put the plus signs here.
02:06
These are our vertical components, ok.
02:10
For 150 newton this is the component, for 100 this was the component and for 200 this is our component, ok.
02:17
Now if we write the x components, so for 150 newton and 100 newton the x components will be in these sides, ok.
02:26
So it will be 100 cos 35 degree and this was for 100 newton and for 150 newton it will be 150 cos 35, sorry it will be cos 65 degree, ok.
02:42
And for 200 the x component will be in negative x axis and it will be 200 cos 35 degree.
02:50
So first of all if we find the net force magnitude in x direction, so the same side, same sided components will be add up, so 100 cos 35 degree plus 150 cos 65 degree minus, because 200 cos 35 degree is in opposite direction, so we will use minus here, minus 200 cos 35 degree, this value...