Question

Question 15 Two Lens System An object is placed 201 cm to the left of a positive lens of focal length 50.0 cm. A "mystery" lens is placed 113 cm to the left of original lens (so that it is located between the original lens and the object). The final image of this two-lens system appears on a screen located 300.0 cm behind (to the right) of the original lens. Calculate the focal length of the "mystery" lens. Note : this question originally stated that the final image was inverted; but depending on your individual numbers, the image could possibly turn out to be upright. I've adjusted the wording and modified the figure accordingly. If you missed this one, it will not count against you.

          Question 15

Two Lens System

An object is placed 201 cm to the left of a positive lens of focal length 50.0 cm. A "mystery" lens is placed 113 cm to the left of original lens (so that it is located between the original lens and the object). The final image of this two-lens system appears on a screen located 300.0 cm behind (to the right) of the original lens. Calculate the focal length of the "mystery" lens.

Note : this question originally stated that the final image was inverted; but depending on your individual numbers, the image could possibly turn out to be upright. I've adjusted the wording and modified the figure accordingly. If you missed this one, it will not count against you.

Show more…

Question 15

Two Lens System

An object is placed 201 cm to the left of a positive lens of focal length 50.0 cm. A "mystery" lens is placed 113 cm to the left of original lens (so that it is located between the original lens and the object). The final image of this two-lens system appears on a screen located 300.0 cm behind (to the right) of the original lens. Calculate the focal length of the "mystery" lens.

Note : this question originally stated that the final image was inverted; but depending on your individual numbers, the image could possibly turn out to be upright. I've adjusted the wording and modified the figure accordingly. If you missed this one, it will not count against you.

Added by Dakota A.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supreeta N

06/06/2023

Step 1

To find the focal length of the mystery lens, we need to calculate its distance from the original lens and Show more…

Show all steps

lock

Thanks for your feedback!

An object is placed 201 cm to the left of a positive lens of focal length 50.0 cm. A "mystery" lens is placed 113 cm to the left of original lens (so that it is located between the original lens and the object). The final image of this two-lens system appears on a screen located 300.0 cm behind (to the right) of the original lens. Calculate the focal length of the "mystery" lens. Note : this question originally stated that the final image was inverted; but depending on your individual numbers, the image could possibly turn out to be upright. I've adjusted the wording and modified the figure accordingly. If you missed this one, it will not count against you.

Play audio

Feedback

Powered by NumerAI

Supreeta N and 77 other subject Physics 101 Mechanics educators are ready to help you.

Ask a new question

Labs

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

Key Concepts

Recommended Videos

Recommended Textbooks

Transcript

00:01 Hello students in the question.

00:02 We are given two lens here.

00:04 We have one mystery lens and another is convex lens.

00:07 So here we have distance between two lenses.

00:16 It is equal to 113 centimeter according to data given question here for mystery lens mystery lens.

00:32 We have object distance.

00:35 It is given as minus 201 centimeter.

00:40 Here we are using sign convention that is towards right distances.

00:49 They are positive while towards left distances are negative.

00:56 So here we have focal length f1 and image distance v1.

01:03 We have formula 1 upon f1 is equal to 1 upon v1 minus 1 upon v1.

01:11 Here f is focal length of the lens v denotes image distance from the lens and u is object distance from the lens.

01:41 So here we can write we have here 1 upon f1 is equal to 1 upon v1 minus of 1 upon minus 201.

01:55 From here we have 1 upon f1 is equal to 1 upon v1 plus 1 upon 201.

02:05 Let this be equation number 1 in the question.

02:10 We are given that final image is formed at 300 centimeter from original lens here as final image is formed at v equal to 300 centimeter.

02:33 This is greater than 2 times focal length distance...

Ace is your personal tutor. It breaks down any question with clear steps so you can learn.

Start Using Ace

Continue solving this problem

Create a free account to:

View full step-by-step solution
Ask follow-up questions with Ace AI
Save progress and study later