00:01
Okay, so we're looking at ratios of sound intensities.
00:04
So in the first part, in a, we're told that the first intensity is 17 decibels more than the second.
00:19
So we're looking at the difference here, so beta 2 minus beta 1.
00:24
So if the first one is 17 decibels higher than when you subtract.
00:31
Beta 2 minus beta 1, you're going to get negative 17 .0 decibels.
00:39
So we can use the equation that beta equals 10 times the log of the intensity over i0, so initial intensity.
00:58
So what we can do is set this up for both the beta 1 and beta 2.
01:05
So we have negative 17 decibels is equal to.
01:11
So beta 2, which is going to be 10 times the log of i2 over i0.
01:22
And then minus beta 1, which is going to be 10 times the log of i0.
01:33
Over i not now we can simplify this a bit let's just divide everything by 10 to get rid of the 10 out in front so that's going to give us negative 1 .7 decibels over here and then log of i2 over i not minus log of i 1 over i not so then we can further simplify it to get rid of the log of i 1 over i not so then we can further simplify it to get rid of the we raise 10 to the power of what is on both sides...