Question 15 Not yet answered Marked out of 1.00 Flag question Find the change in entropy (in units of J/K) of 263 gm of liquid water at 0°C when heated to temperature 26°C. a. 115.01 b. 100.01 c. 113.01 d. 145.01 e. -2584.96 Clear my choice
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18 J/g°C) ΔT = change in temperature (26°C - 0°C = 26°C) ΔQ = 263 g * 4.18 J/g°C * 26°C ΔQ = 279,091.6 J Show more…
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