Question 15 Not yet answered Marked out of 1.00 Flag question Solve for $x$ in the following linear inequality: $3x + 2 < 6x - 8$. Select one: a. $x > \frac{10}{3}$ b. $x \le \frac{10}{3}$ c. $x < 6$ d. $x < \frac{2}{3}$
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Step 1: Subtract $3x$ from both sides of the inequality: $3x + 2 - 3x < 6x - 8 - 3x$ $2 < 3x - 8$ Show more…
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