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Question 15 You roll 10 fair six-sided dice. 1. What is the probability of getting exactly two fives? 2. What is the probability of getting three or more fives? a) P(exactly two fives) = 0.290, P(three or more fives) = 0.224 b) P(exactly two fives) = 0.040, P(three or more fives) = 0.760 c) P(exactly two fives) = 0.444, P(three or more fives) = 0.112 d) P(exactly two fives) = 0.122, P(three or more fives) = 0.500 Oc Od Oa Ob

          Question 15
You roll 10 fair six-sided dice.
1. What is the probability of getting exactly two fives?
2. What is the probability of getting three or more fives?
a) P(exactly two fives) = 0.290, P(three or more fives) = 0.224
b) P(exactly two fives) = 0.040, P(three or more fives) = 0.760
c) P(exactly two fives) = 0.444, P(three or more fives) = 0.112
d) P(exactly two fives) = 0.122, P(three or more fives) = 0.500
Oc
Od
Oa
Ob

Question 15
You roll 10 fair six-sided dice.
1. What is the probability of getting exactly two fives?
2. What is the probability of getting three or more fives?
a) P(exactly two fives) = 0.290, P(three or more fives) = 0.224
b) P(exactly two fives) = 0.040, P(three or more fives) = 0.760
c) P(exactly two fives) = 0.444, P(three or more fives) = 0.112
d) P(exactly two fives) = 0.122, P(three or more fives) = 0.500
Oc
Od
Oa
Ob

Added by Chelsea H.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Adi S

07/09/2023

Step 1

The formula for the binomial distribution is: $$P(X = k) = {n \choose k} * p^k * (1 - p)^{(n - k)},$$ where: * $n$ is the number of trials (in this case, 10 rolls of the dice) * $k$ is the number of successes (in this case, 2 fives) * $p$ is the probability of Show more…

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Question 15 You roll 10 fair six-sided dice. 1. What is the probability of getting exactly two fives? 2. What is the probability of getting three or more fives? a) P(exactly two fives) = 0.290, P(three or more fives) = 0.224 b) P(exactly two fives) = 0.040, P(three or more fives) = 0.760 c) P(exactly two fives) = 0.444, P(three or more fives) = 0.112 d) P(exactly two fives) = 0.122, P(three or more fives) = 0.500 Oc Od Oa Ob