00:02
Hello students, hope you all doing great.
00:04
In this question we are given a molecule and in this molecule we have to find out how many nmr signals are possible.
00:10
So now here we can see that there are four methyl groups bonded to the sp2 hybridized carbon.
00:17
All of these four methyl groups are having similar chemical environment.
00:28
Since all the protons are having similar chemical environment, they all give single signal.
00:42
Therefore for this molecule we can say that only one nmr signal is observed.
00:57
In the next molecule we have to find out what type of splitting will it show.
01:02
So the molecule that we have here is this.
01:05
Here we have carbonyl carbon, here we have oxygen and here we have methyl groups like this.
01:11
So this is a, this is b, this is c and this one here is d.
01:21
So now here we can see that for this carbon, it is bonded with the carbon which is bonded with two hydrogen.
01:28
So it will show 2 plus 1 that is 3, that is it will show triplet...