00:01
Everyone, so here in this question we are given that how many alphinis are formed by e2 elimination of each pair from 3 -bromo 3 -4 dimethyl hexane, right, using a strong base such as sodium metoxide.
00:15
So we are given 3 -bromo 3 -4 di -metal hexant, right? so 1, 2, 3, 4, 5 and 6.
00:23
So in the 1 -2 -3 position, we have bromo and we have c .h3.
00:33
And in the 4 position also we have a thh3.
00:37
Right.
00:39
And we are reacting it with a strong base such as n -a -o -c -h -3.
00:45
So damn it, right.
00:48
Right.
00:49
So what will happen here? so there is an edge here, right? so we'll get a double bond here and there will be moat, right? right, minus hpr.
01:01
So we'll get something like this.
01:09
Okay? right...