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Question 18 5 pts Simplify the polar expressions. For r, round to the nearest whole number. For theta, input your answer as exact radians and type pi for $\pi$. $14e^{i\pi/4} \cdot 3e^{i\pi/2} = r \cdot e^{i\theta}$ r= $\theta$ = radians

          Question 18
5 pts
Simplify the polar expressions.
For r, round to the nearest whole number.
For theta, input your answer as exact
radians and type pi for $\pi$.
$14e^{i\pi/4} \cdot 3e^{i\pi/2} = r \cdot e^{i\theta}$
r=
$\theta$ = radians

Question 18
5 pts
Simplify the polar expressions.
For r, round to the nearest whole number.
For theta, input your answer as exact
radians and type pi for π.
14e^iπ/4· 3e^iπ/2 = r · e^iθ
r=
θ = radians

Added by Jose Luis A.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Steven Clarke

03/20/2024

Step 1

14e^(iπ/4) = 14(cos(π/4) + i*sin(π/4)) = 14(cos(π/4) + i*sin(π/4)) 3e^(iπ/2) = 3(cos(π/2) + i*sin(π/2)) = 3(0 + i*1) = 3i Show more…

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Question 18 Simplify the polar expressions. For r, round to the nearest whole number. For theta, input your answer as exact radians and type pi for π. 14e^(iπ/4) * 3e^(iπ/2) = r * e^(iθ) r = θ = radians Question 18 5 pts Simplify the polar expressions For r round to the nearest whole number For theta, input your answer as exact radians and type pi for π. 14e^(iπ/4) * 3e^(iπ/2) = r. r = 0 radians