Question 19 1 pts How many moles of water, \( \mathrm{H}_{2} \mathrm{O} \), are present in \( 75.0 \mathrm{~g} \mathrm{H}_{2} \mathrm{O} \) ? \( 1.35 \times 10^{3} \) moles 7.50 moles 4.16 moles 75.0 moles 4.41 moles
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- Hydrogen (\( \mathrm{H} \)): 1.01 \, \text{g/mol} \times 2 = 2.02 \, \text{g/mol} - Oxygen (\( \mathrm{O} \)): 16.00 \, \text{g/mol} Show more…
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