00:01
Dear students, the question is both 1 butin and 2 butin have cis and trans isomers, whether this statement is true or false.
00:10
Now to see the truthfulness of the statement to check, let us first draw the structures of 1 butin and 2 butin.
00:21
1 is having the double 1 at the first position.
00:28
So here this is 1 butin.
00:32
Then ch, ch 2, cs3, then 2 butin, 2 butin is like this, this is cs3, c h, double bond ch, c s3, this is 2 butin.
00:56
Now to have c -sysmars, the carbon atom or to show geometrical isomers, the carbon atom of the double bond, the carbon atoms attach to the double bond, they might must attach to different atoms or groups.
01:10
Now if we check here, this carbon is attached to two hydrogen atoms.
01:15
Therefore, this will not show any geometrical isomergymergium or cis -transisomer.
01:21
Therefore, this compound has no cis -transisomers.
01:33
Whereas if we check here, it is having two butin is having two different atoms or groups attached to the carbon atoms attached to the double bond here hydrogen hand.
01:49
So the different atoms or groups are here cs3 and h, these two are different and these two are also different...