Question 19 2 pts What is the mass of sodium carbonate (molar mass: \( 105.99 \mathrm{~g} / \mathrm{mol} \) ) needed to make 450.0 mL of a 0.597 M solution? none of these 47.7 g 28.5 g 490 g 49.0 g
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- Molarity (M) = 0.597 M - Volume (V) = 450.0 mL = 0.450 L (since 1 L = 1000 mL) - Molar mass of sodium carbonate (Na₂CO₃) = 105.99 g/mol Show more…
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