Question 1a Explain the solubility results for boric acid in terms of polarity/ionisation of the solvent and solute. Answer text Question 3 Rich text editor
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Boric acid is a weak acid that can partially ionize in water, producing borate ions (B(OH)4-) and hydrogen ions (H+). It is a polar molecule due to the presence of hydroxyl (–OH) groups, which can form hydrogen bonds with water. Show more…
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Boric acid (H3BO3) dissociates in water following the reaction: H3BO3 ⇌ H+ + H2BO3-. You dissolve a certain amount of H3BO3 in pure water, creating an aqueous solution. You are able to measure the undissociated fraction (i.e., H3BO3), and you find it has a concentration [H3BO3] = 16 mmol m-3. You also measure pH and realize that the solution has remained perfectly neutral (pH = 7). [You can ignore the second and third dissociations of H3BO3 for this problem.] (a) Determine if H3BO3 is a strong or weak acid. To do so, calculate the dissociation constant Ka and determine whether pKa > 2 or not. [2 points] (b) The total boron concentration in seawater is 420 mmol m-3. You create a new H3BO3 solution by dissolving exactly 420 mmol m-3 of H3BO3 in pure water. Determine the pH of the resulting solution, as well as the concentrations of the dissociated (H2BO3-) and undissociated (H3BO3) components. [3 points]
Sri K.
Ionisation of boric acid in aqueous medium gives which one of the following? (a) $\left[\mathrm{BO}_{3}\right]^{3-}$ (b) $\left[\mathrm{B}(\mathrm{OH})_{4}\right]$ (c) $\left[\mathrm{B}(\mathrm{OH})_{2} \mathrm{O}\right]^{-}$ (d) $\left[\mathrm{B}(\mathrm{OH}) \mathrm{O}_{2}\right]^{2-}$
Ionisation of boric acid in aqueous medium gives which one of the following? (a) $\left[\mathrm{BO}_{3}\right]^{-}$ (b) $\left[\mathrm{B}(\mathrm{OH})_{1}\right]^{-}$ (c) $\left[\mathrm{B}(\mathrm{OH})_{2} \mathrm{O}\right]^{-}$ (d) $\left[\mathrm{B}(\mathrm{OH}) \mathrm{O}_{2}\right]^{2-}$
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