00:01
Hello students in this question we have to find the equivalent torsional spring constant of the system or equivalent torsional spring constant.
00:14
So let us denote it as kep that is equivalent torsional spring constant.
00:20
In this case given that given k1, k2, k3 and k4 or torsional strings various k5 and k6 are linear strings.
00:41
From the diagram first let's consider the first three springs that is k1, k2, k3.
00:54
So here k1, k2, k3 are connected in series.
01:05
So for the springs that are connected in series we can find the equivalent spring constant as keq prime and this is equal to 1 by k1 plus 1 by k2 plus 1 by k3.
01:25
So therefore we get 1 by k equivalent prime is equal to k2, k3 plus k1, k3 plus k1, k2 divided by k1, k2, k3.
01:43
Now if we take the reciprocal of this we get k equivalent is equal to k1, k2, k3 divided by k2, k3 plus k1, k3 plus k1, k2.
02:00
Now we have to find the equivalent spring constant of the entire system.
02:06
So we develop the work done by the potential energy u...