QUESTION 2 A 2.0 kg softball is pitched to you at 20. m/s. You hit the ball back along the same path, and at the same speed. If the bat was in contact with the ball for 0.10 s, the average force the bat exerted was Îź 40. Îť. 0.65 kN. Ozero. 0.80 kN. 0.40 kN.
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The impulse is equal to the change in momentum. $$J = \Delta p = m(v_f - v_i)$$ where $J$ is the impulse, $\Delta p$ is the change in momentum, $m$ is the mass, $v_f$ is the final velocity, and $v_i$ is the initial velocity. Show more…
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