Question

Question 2. A carrier ( s(t)=100 cos left(2 pi .10^{9} mathrm{t} ight) ) of an FM transmitter is modulated with a tone signal. For this transmitter, a 1 V (rms) tone produces a deviation of 30 kHz . Determine the amplitude and frequency of all FM signal components (spectral lines) that are greater than ( 1 % ) of the unmodulated carrier amplitude for the following modulating signals: a. ( m(t)=2 cos left(3 pi cdot 10^{4} t ight) ). b. ( m(t)=cos left(6 pi cdot 10^{4} t ight) ).

          Question 2.
A carrier ( s(t)=100 cos left(2 pi .10^{9} mathrm{t}
ight) ) of an FM transmitter is modulated with a tone signal. For this transmitter, a 1 V (rms) tone produces a deviation of 30 kHz . Determine the amplitude and frequency of all FM signal components (spectral lines) that are greater than ( 1 % ) of the unmodulated carrier amplitude for the following modulating signals:
a. ( m(t)=2 cos left(3 pi cdot 10^{4} t
ight) ).
b. ( m(t)=cos left(6 pi cdot 10^{4} t
ight) ).

Question 2.
A carrier ( s(t)=100 cos left(2 pi .10^9 mathrmt
ight) ) of an FM transmitter is modulated with a tone signal. For this transmitter, a 1 V (rms) tone produces a deviation of 30 kHz . Determine the amplitude and frequency of all FM signal components (spectral lines) that are greater than ( 1 % ) of the unmodulated carrier amplitude for the following modulating signals:
a. ( m(t)=2 cos left(3 pi cdot 10^4 t
ight) ).
b. ( m(t)=cos left(6 pi cdot 10^4 t
ight) ).

Added by Quang H.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Eduard Sanchez

10/28/2024

Step 1

- Carrier signal: \( s(t) = 100 \cos(2 \pi \cdot 10^9 t) \) - Frequency deviation for 1 V (rms) tone: 30 kHz - Unmodulated carrier amplitude: 100 Show more…

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