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Question 2. A fixed-fixed steel column has length of 3 m, radius of gyration of column cross sectional area of 23.09 mm and modulus of elasticity of 210 GPa and yield strength of 220 MPa, calculate the allowable stress with a safety factor of 2. For A < B use: ?cr = [0.658^(?/?c)]?Y For A > B use: ?cr = 0.877?E For A = B use: ?cr = 0.39?Y

          Question 2. A fixed-fixed steel column has length of 3 m, radius of gyration of column cross sectional area of 23.09 mm and modulus of elasticity of 210 GPa and yield strength of 220 MPa, calculate the allowable stress with a safety factor of 2. For A < B use: ?cr = [0.658^(?/?c)]?Y For A > B use: ?cr = 0.877?E For A = B use: ?cr = 0.39?Y
        
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Question 2. A fixed-fixed steel column has length of 3 m, radius of gyration of column cross sectional area of 23.09 mm and modulus of elasticity of 210 GPa and yield strength of 220 MPa, calculate the allowable stress with a safety factor of 2. For A < B use: ?cr = [0.658^(?/?c)]?Y For A > B use: ?cr = 0.877?E For A = B use: ?cr = 0.39?Y

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Mechanics of Materials
Mechanics of Materials
R. C. Hibbeler 10th Edition
Chapter 13
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Question 2 A fixed-fixed steel column has length of \( 3 \mathrm{~m} \), radius of gyration of column cross sectional area of \( 23.09 \mathrm{~mm} \) and modulus of elasticity of 210 GPa and yield strength of \( 2.20 \mathrm{MPa} \), calculate the allowable stress with a safety factor of 2 For \( \mathrm{A}<\mathrm{B} \) use: \[ \sigma_{c r}=\left[0.658^{\left({ }^{\sigma_{Y}} / \sigma_{E}\right)}\right] \sigma_{Y} \] For \( A>B \) use: \[ \sigma_{c r}=0.877 \sigma_{R} \] For \( A=B \) use: \[ \sigma_{c r}=0.39 \sigma_{Y} \]
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