Determine whether the given differential equation is EXACT and, if so, solve it. (4t^3y^3 - 2ty)dt + (3t^4y^2 - t^2)dy = 0
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The given equation is: \[ (4t^3y^3 - 2ty)dt + (3t^4y^2 - t^2)dy = 0 \] Here, \( M(t, y) = 4t^3y^3 - 2ty \) and \( N(t, y) = 3t^4y^2 - t^2 \). Show more…
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