00:01
Here, movement of inertia about x -axis, let's suppose this is the x -axis, then it will be, this is the, let's suppose, da, that is small area of this strip, then i -x -x will be equal to x, sorry, y -square into da, where y is this particular length.
00:29
So now we can write here if this is da, so it can be written as 1 minus x because x is the coordinate of this point.
00:53
So this whole length is 1.
00:56
So this will be 1 minus x.
00:59
And the width of this will be taken as dy.
01:03
So it can be written as 1 minus x into dy.
01:07
So area of this strip is da equals to 1 minus x into dy.
01:13
So we can write here ixx equals to y square into 1 minus x into dy.
01:23
Now we can substitute x equals to here y power 3 by 2...