00:01
You are given two point charges with the same magnitude of, let's see, 4 .12 times 10 to the negative 10 coulombs, but opposite signs.
00:17
So if the electric field midway between these two charges is 270 newtons per coulomb, calculate the separation between the charges.
00:28
So let's take a look at this and we have a few answer choices.
00:31
So we have the distance, this is d, this is going to be the magnitudes q and so the, sorry no we don't have the distance that's what we're looking for.
00:47
We're looking for the distance and this here is going to be e -net okay.
00:54
The electric field midway between the two charges.
00:58
So the separation is going to be calculated using, let's see, let's do e equals 1 over 4 pi epsilon naught q over r squared.
01:14
So this is 9 .0 times 10 to the 9 newton meters squared per coulomb squared and then we have q over r squared.
01:29
We actually have q that is going to be 4 .12 times 10 to the negative 10 over and then the r squared is the same as d over 2 squared and this is going to be the electric field due to the positively charged point so this is the plus q and then we have the negatively charged one so e2 is going to be a same formula but let's actually write it like this so this is going to be 9 .0 times 10 to the the ninth and this is going to be the same thing and here we have 4 .12 times 10 to the negative 10 c over d over 2 squared and let's actually simplify these so let's get okay this is what we got let's see, so the e net which we have is equal to e1 plus e2...