00:01
In this problem it is said that we have a shipment of 18 bottles of a drug.
00:05
5 of the bottles are tested.
00:07
4 of the 18 are contaminated and we want to find the probability that at least 3 of the tested bottles are contaminated.
00:14
So the required probability will be the number of favorable outcomes divided by the total number of outcomes.
00:19
First of all consider the total number of outcomes.
00:21
That will be the number of ways of selecting 5 bottles to be tested.
00:25
So out of the 18 bottles any 5 are selected at random.
00:28
This can be done in 18 c5 ways.
00:30
Here we use c which represents combination.
00:33
And we use combination and not permutation in this case because the order of selection of the bottles does not matter.
00:39
Next consider the number of favorable outcomes.
00:41
That will be the number of ways there are at least 3 bottles which are contaminated amongst the tested bottles.
00:47
So note that a total of 4 bottles are contaminated.
00:50
So there are 2 ways that we can have at least 3 bottles contaminated.
00:54
That is if we have exactly 3 bottles or if we have exactly 4 bottles contaminated.
01:00
So first of all let's consider the number of ways we can select 5 bottles so that exactly 3 are contaminated...