00:01
Hello, in part a of this question we have to calculate the mass of the gas on the earth.
00:05
The mass m is a constant both on the earth and on the moon.
00:12
Now the mass of the gas in lbm can be given by m is equal to wm divided by gem.
00:19
Here wm is the weight of the gas on the moon and gm is the acceleration due to gravity on the moon.
00:25
Let's substitute the values.
00:27
So it equals 3 .5 lbf divided by 5 .5.
00:32
0 .47 feet per second square which equals 0 .64 lbm.
00:40
Now since 1 lbm is equal to 0 .45 kilogram, the mass of gas in kilogram can be written as m -dash is equal to 0 .64 into 0 .45 kilogram, which can be written as equal to 0 .3 kilogram.
01:01
Therefore the mass of the gas on the earth in lbm is obtained as m is equal to 0 .64 lbm and the mass of the gas in kilogram is obtained as m -dash is equal to 0 .3 kilogram.
01:19
Now let's solve part b.
01:21
The weight of gas on the earth is we is equal to 6 multiplied by wm equals 6 into 3 .5 lbf which equals 21 lbf.
01:37
Now since 1lbf is equal to 4 .45 newton, the weight of the gas on the earth in newton can be given by w .e.
01:51
Dash is equal to 21 into 4 .45 newton, which equals 93 .45 newton.
02:05
Therefore the weight in lbf of the gas on the earth is obtained as we is equal to 21 lbf and the weight in newton is obtained as we -e -dash is equal to 93 .45 newton.
02:21
Now in part c, assuming the volume of the gas remains constant, the density can be expressed as d is equal to m divided by v...