00:01
Hi, so we are to calculate the amount of heat required for this reaction.
00:06
So let's write first the temperatures involved.
00:08
We have 23 degrees celsius.
00:10
This is the initial temperature of liquid ethanol and we are to heat this up to 78 .3 degrees celsius which is the boiling point of ethanol.
00:21
So that means there will be temperature change delta t and there will also be phase change.
00:27
So the amount of heat required for delta t or change in temperature will be q1 and then for phase change this will be q2.
00:36
So the total amount of heat qt will be equivalent to q1 plus q2.
00:42
Q1 is the heat required for temperature change so that will be mass multiplied by the specific heat capacity and then the change in temperature for liquid, that's right here, ethanol plus the number of moles and then the enthalpy of vaporization, delta h of vaporization.
01:02
And let's plug in the information that we have.
01:05
We have 42 grams of ethanol multiplied by the specific heat capacity 2 .46 joules per gram degree celsius...