00:01
Hello students in this question given as the shock absorbs in the each wheel of the car is 2 is equals to 1 upon under root 1 minus omega upon p square whole square plus 4 into 0 .1221 square and omega upon p whole square.
00:30
In this question we have to calculate the damping factor that is omega by p.
00:36
So, let us consider the omega by p is equals to x.
00:41
So, we will substitute the x in the above equation.
00:45
So, 2 will be equal to the 1 upon under root 1 minus x square whole square plus 4 after multiplication this value or let 0 .1221 square into x square.
01:05
Now, we can write 4 into after squaring on the both sides.
01:11
So, 1 minus x square whole square plus 0 .0596 x square minus 1 is equals to 0.
01:23
Now, let f of x is a function that is equals to the 1 minus x square whole square 0 .0596 square minus 1.
01:43
Using the secant method will use the will put the value of x is equals to 2.
01:49
So, in this x is equals to 2 is equals to after calculation this is equals to 3 and when we put the value of 1.
01:57
So, this is this will get minus 0 .7614.
02:03
Since we can see that the function of that is a 2 and a function of 1 multiplication is a negative.
02:13
So, this is less than 0.
02:14
Now, we can see that so root of the above equation lies between between 1 and 2.
02:27
So, the root is a is equals to 1 and b is equals to.
02:35
Now, the using the second method this is the function is equals to a into f of b minus b into f of a upon f of b minus f of a.
02:56
Now, we will substitute the values that is a is equals to 1 and f of b is equals to 3...