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QUESTION 27 Dehydration of 2-methyl-3-pentanol with a strong acid (H+) at a high temperature -180°C 2-methyl-2-pentene ? dimethylpentene 3-methyl-2-pentene ? di-s-butylether ? more than one of these

          QUESTION 27
Dehydration of 2-methyl-3-pentanol with a strong acid (H+) at a high temperature -180°C
2-methyl-2-pentene
? dimethylpentene
3-methyl-2-pentene
? di-s-butylether
? more than one of these

Added by Christopher K.

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition

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Solved by Expert Dj Tan

Step 1

Dehydration of an alcohol, in this case, 2-methyl-3-pentanol, involves the removal of a water molecule (H2O) from the alcohol molecule. This reaction is facilitated by a strong acid (H+) and high temperature, leading to the formation of an alkene. Show more…

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Question 27: Dehydration of 2-methyl-3-pentanol with a strong acid (H+) at a high temperature (-180°C) yields 2-methyl-2-pentene, dimethylpentene, 3-methyl-2-pentene, di-s-butylether, or more than one of these.