The chi-square values (for interval estimation) for a sample size of 21 at 95% confidence are 9.591 and 34.170 2.700 and 19.023 8.260 and 37.566 -1.96 and 1.96
Added by Jose V.
Step 1
Step 1: Calculate the degrees of freedom for the chi-square distribution: df = n - 1 = 21 - 1 = 20 Show more…
Show all steps
Close
Your feedback will help us improve your experience
David Nguyen and 87 other Intro Stats / AP Statistics educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Use the given degree of confidence and sample data to construct a confidence interval for the population mean μ. Assume that the population has a normal distribution. n = 12, x̄ = 28.3, s = 4.8, 99% confidence 23.91 < μ < 32.69 24.01 < μ < 32.59 24.00 < μ < 32.60 24.53 < μ < 32.07
Anna D.
Let X have a gamma distribution with alpha=4, and beta = 3. Find P(9<X<27). 0.496 0.979 0.511 0.626 A random sample of 100 observations produced a sample proportion of 0.25. An approximate 90% confidence interval for the population p is: 0.248 and 0.252 0.179 and 0.321 0.246 and 0.254 0.423 and 0.567
Madhur L.
We have provided a sample standard deviation and sample size. In each case, use the one-standard-deviation $x^{2}$ -test and the one-standard-deviation $x^{2}$ -interval procedure to conduct the required hypothesis test and obtain the specified confidence interval. $s=6$ and $n=26$ a. $H_{0}: \sigma=5, H_{a}: \sigma>5, \alpha=0.01$ b. $98 \%$ confidence interval
Inferences for Population Standard Deviations
Inferences for One Population Standard Deviation
Recommended Textbooks
Elementary Statistics a Step by Step Approach
The Practice of Statistics for AP
Introductory Statistics
Transcript
Watch the video solution with this free unlock.
EMAIL
PASSWORD