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Question 29 If we halve the distance from an isotropic source of EM waves, the electric field amplitude will be 1/2 of its initial value. 1/4 of its initial value. $\sqrt{2}$ of its initial value. $\frac{1}{\sqrt{2}}$ of its initial value. 2 times its initial value.

Name: question 29 if we halve the distance from an isotropic source of em waves the electric field amplitude will be 12 of its initial value 14 of its initial value sqrt2 of its initial value frac 70794
Uploaded: 2022-01-12T07:19:36-08:00
Duration: 1 min 1 s
Channel: Narayan Hari
Description: question 29 if we halve the distance from an isotropic source of em waves the electric field amplitude will be 12 of its initial value 14 of its initial value sqrt2 of its initial value frac 70794

          Question 29
If we halve the distance from an isotropic source of EM waves, the electric field amplitude will be
1/2 of its initial value.
1/4 of its initial value.
$\sqrt{2}$ of its initial value.
$\frac{1}{\sqrt{2}}$ of its initial value.
2 times its initial value.

$question 29 if we halve the distance from an isotropic source of em waves the electric field amplitude will be 12 of its initial value 14 of its initial value sqrt2 of its initial value frac 70794$

Added by Alexis L.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Narayan Hari

01/12/2022

Step 1

That is, $I \propto \frac{1}{r^2}$, where $I$ is the intensity and $r$ is the distance. Show more…

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Question 29 If we halve the distance from an isotropic source of EM waves, the electric field amplitude will be 1/2 of its initial value. 1/4 of its initial value. $\sqrt{2}$ of its initial value. $\frac{1}{\sqrt{2}}$ of its initial value. 2 times its initial value.