Question 3 (1 point) Solving the following system, one would find that: \[ \begin{aligned} 2 x-2 y+2 z & =5 \\ -3 x+y-z & =0 \\ x-y+z & =6 \end{aligned} \] the planes are all coincident the planes are all parallel the planes intersect along a common line two planes are parallel and intersect the third
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Step 1: Write down the equations of the planes: \[ \begin{aligned} 2x - 2y + 2z &= 5 \quad \text{(Equation 1)} \\ -3x + y - z &= 0 \quad \text{(Equation 2)} \\ x - y + z &= 6 \quad \text{(Equation 3)} \end{aligned} \] Show more…
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