00:01
So, here in this question we are considering a beam whose cross section is subjected to the internal symmetry where we are given the value of m that is equal to 70k inches.
00:09
We are having the value of theta that is 75 degree and we are given the value of a that is 3 inches from here.
00:16
So basically this is the beam we are considering here.
00:21
This is the y direction, this from here is the x direction that is the angle theta from here which is in h direction that from here is moving as m sin of theta and this from here is giving as moving as m cos of theta.
00:37
So here we can say that m of g from here is equal to m cos of theta which means the value of m of g is equal to 70 which is multiplied by the cos of 75 degree.
00:48
So we can say that m of g from here is equal to 70 that is multiplied by 0 .2588.
00:54
So simplifying the term we get the value of m of g from here that is equal to 18 .11 kilo inches.
01:00
This is the value of the mg from here.
01:03
Now we are considering about my.
01:05
So my is equal to m which is multiplied by the sin of theta that from here is equal to 70 multiplied by the sin of 75 degree.
01:14
So the value of my in this case is equal to 70 multiplied by 0 .96659...